Alcohols & phenols & ethers practice · Medium

Option B is correct because both the assertion and reason are correct statements, but the reason is not the correct explanation of the assertion. HI cleaves the ether linkage to form phenol and methyl iodide, not chloromethane, and the reason explains the electron density but not the cleavage.

Option A is correct because the alcohol P is oxidized to a ketone B, which then reacts with Grignard reagent to form a tertiary alcohol after hydrolysis, indicating P must be a secondary alcohol.

Option C (Zymase) is correct because zymase is the enzyme complex that catalyzes the fermentation of glucose and fructose into ethanol.

Option D (All of these) is correct because $KHS{{O}}_4$, ${{P}}_2{{O}}_5$, and concentrated ${{H}}_2{{SO}}_4$ are all dehydrating agents that can dehydrate glycerol to form acrolein.

Option D is correct because phenol is less acidic than carbonic acid ($H_2CO_3$), and phenol does not react with $NaHCO_3$ solution due to its lower acidity.

Option C (Glycerol) is correct because Dunstan's test is specifically used to identify the presence of glycerol.