Back to 14 TH GROUP ELEMENTS (P-BLOCK)

Your Progress

0 / 197 Answered

Correct

Incorrect

Accuracy

JEE • CHEMISTRY • 14 TH GROUP ELEMENTS (P-BLOCK)

14 th group elements (p-block) practice · Mixed difficulty

Try a question, then open “View answer” to check it. Sign in to submit answers and save progress.

Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

Take a chapter quiz →

Showing 1-30 of 197 questions

1 Medium

1 of 197

Understanding +4 | -1

Which of the following does not exist

View answer and explanation

Correct option: A

SiCl_6^{ - 2}

Option A (

SiCl_6^{ - 2}

) is correct because Silicon, due to its smaller size and lack of available d-orbitals for bonding, cannot accommodate six large chloride ions around it.

2 Hard

2 of 197

Remembering +4 | -1

Newton’s alloy contains :

View answer and explanation

Correct option: A

Bi, Sn, Pb

Option A (Bi, Sn, Pb) is correct because Newton's alloy is a fusible alloy composed of bismuth (Bi), tin (Sn), and lead (Pb).

3 Medium

3 of 197

Remembering +4 | -1

Which is pyrosilicate :-

View answer and explanation

Correct option: A

{Zn}_3 {Si}_2 {O}_7 \cdot {Zn}({OH})_2

Option A (

{Zn}_3 {Si}_2 {O}_7 \cdot {Zn}({OH})_2

) is correct because pyrosilicates contain the

Si_2O_7^{-6}

unit, which is present in this compound.

4 Easy

4 of 197

Remembering +4 | -1

Commercially important ore of lead is:

View answer and explanation

Correct option: D

Galena

Option D (Galena) is correct because Galena (PbS) is the most commercially important ore of lead.

5 Hard

5 of 197

Analyzing +4 | -1

Assertion:

{SiF}_6^{2-}

is known but

{SiCl}_6^{2-}

is not

Reason: Size of fluorine is small and its lone pair of electrons interacts with

d

-orbitals of

Si

strongly.

View answer and explanation

Correct option: A

If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.

Option A (If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion) is correct because the small size of fluorine allows for effective interaction of its lone pairs with the d-orbitals of silicon, stabilizing the

SiF_6^{2-}

ion, while the larger size of chlorine prevents this in

SiCl_6^{2-}

6 Medium

6 of 197

Remembering +4 | -1

The correct statement with respect to carbon monoxide is:

View answer and explanation

Correct option: B

It reacts with haemoglobin in red blood cells.

Option B is correct because carbon monoxide (CO) has a high affinity for hemoglobin, binding more strongly than oxygen and thus interfering with oxygen transport in red blood cells.

7 Easy

7 of 197

Remembering +4 | -1

In general, silicones:

View answer and explanation

Correct option: D

All of these

Option D (All of these) is correct because silicones generally have high thermal stability, are resistant to oxidation, and are water repellent.

8 Easy

8 of 197

Remembering +4 | -1

Silicon is

View answer and explanation

Correct option: A

Semiconductor

Option A (Semiconductor) is correct because silicon (Si) is a material with electrical conductivity between that of a conductor and an insulator.

9 Easy

9 of 197

Analyzing +4 | -1

Assertion (A) : Diamond is insulator and graphite is conducting.

Reason (R): C-atom is

s p^3

hybridised in both.

View answer and explanation

Correct option: C

\mathbf{A}

is true but

\mathbf{R}

is false.

Option C is correct because the assertion is true, but the reason is false. Diamond is an insulator and graphite is conducting, but the hybridization is different.

10 Medium

10 of 197

Understanding +4 | -1

Assertion (A) :

{SiF}_6^{2-}

is known but

{SiCl}_6^{2-}

is not known.

Reason (R) : Interaction of

F

lone pair electrons with

{Si}

is stronger than that of chlorine and due to smaller size of

{F}

steric repulsion will be less.

View answer and explanation

Correct option: A

Both

\mathbf{A}

and

\mathbf{R}

are true and

\mathbf{R}

is the correct explanation of

\mathbf{A}

Option A is correct because both the assertion and the reason are true, and the reason correctly explains why

{SiF}_6^{2-}

exists while

{SiCl}_6^{2-}

does not, relating to the interaction of lone pairs and steric hindrance.

11 Easy

11 of 197

Remembering +4 | -1

Moderate electrical conductivity is shown by

View answer and explanation

Correct option: B

Graphite

Option B (Graphite) is correct because graphite has a layered structure with delocalized electrons, allowing it to conduct electricity moderately.

12 Easy

12 of 197

Remembering +4 | -1

The hybridisation of carbon in diamond, graphite and fullerenes are respectively.

View answer and explanation

Correct option: A

S{p^3},S{P^2},S{P^2}

Option A (

S{p^3},S{P^2},S{P^2}

) is correct because carbon in diamond is

sp^3

hybridized, in graphite is

sp^2

hybridized, and in fullerenes is also

sp^2

hybridized.

13 Medium

13 of 197

Understanding +4 | -1

Assertion (A):

\mathrm{CaC}_2

is interstitial carbide.

Reason (R): Calcium ions are present in the Interstices.

View answer and explanation

Correct option: D

Both (A) and (R) are false

Option D is correct because both the assertion and the reason are false. Calcium carbide (

CaC_2

) is not an ionic carbide, and the ions present are

Ca^{2+}

and

C_2^{2-}

14 Medium

14 of 197

Understanding +4 | -1

The tendency of catenation in group – 14 elements follows the order

View answer and explanation

Correct option: B

C > > Si > Ge = Sn

Option B (

C > > Si > Ge = Sn

) is correct because the catenation tendency decreases down the group due to decreasing bond strength.

15 Easy

15 of 197

Remembering +4 | -1

Which one of the following is used as an acid flux in metallurgy?

View answer and explanation

Correct option: B

\mathrm{Si}{\mathrm{O}_2}

Option B (

\mathrm{Si}{\mathrm{O}_2}

) is correct because silica (

\mathrm{Si}{\mathrm{O}_2}

) is an acidic oxide and is used as an acid flux to remove basic impurities in metallurgy.

Explore Other Chapters in CHEMISTRY

View All →

P-BLOCK ELEMENTS 736 MCQs Equilibrium 696 MCQs STRUCTURE OF ATOM 634 MCQs THERMODYNAMICS 536 MCQs CHEMICAL BONDING & MOLECULAR STRUCTURE 514 MCQs SOLUTIONS 480 MCQs

16 Medium

16 of 197

Remembering +4 | -1

Nature of

C{O_2}\,\,\& \,\,Si{O_2}

are respectively.

View answer and explanation

Correct option: C

Acidic, acidic

Option C (Acidic, acidic) is correct because both carbon dioxide (

\mathrm{CO_2}

) and silicon dioxide (

\mathrm{SiO_2}

) are acidic oxides.

17 Medium

17 of 197

Remembering +4 | -1

Which fuel has the highest calorific value (kJ/kg)?

View answer and explanation

Correct option: B

Kerosene

Option B (Kerosene) is correct because kerosene has a higher calorific value compared to charcoal, wood, and cow dung, meaning it releases more heat per unit mass when burned.

18 Easy

18 of 197

Remembering +4 | -1

The hottest part of the Bunsen burner flame is:

View answer and explanation

Correct option: B

A little below the tip of the flame

Option B (A little below the tip of the flame) is correct because the hottest part of a Bunsen burner flame is located just below the tip of the inner blue cone, where complete combustion occurs.

19 Easy

19 of 197

Remembering +4 | -1

Which of the following isotope of carbon is radioactive?

View answer and explanation

Correct option: C

{ }^{14} {C}

Option C (

{ }^{14} {C}

) is correct because it is a radioactive isotope of carbon used for radiocarbon dating.

20 Easy

20 of 197

Remembering +4 | -1

The ability of a substance to assume two or more crystalline structures is called:

View answer and explanation

Correct option: C

Polymorphism

Option C (Polymorphism) is correct because polymorphism refers to the ability of a substance to exist in two or more different crystalline forms.

21 Easy

21 of 197

Understanding +4 | -1

The percentage of s-character of the hybrid orbitals of carbon in graphite and diamond are respectively

View answer and explanation

Correct option: A

33, 25

Option A (33, 25) is correct because in graphite, carbon is

sp^2

hybridized (33% s-character), and in diamond, carbon is

sp^3

hybridized (25% s-character).

22 Medium

22 of 197

Remembering +4 | -1

When gypsum is heated to

393 K,

it forms:

View answer and explanation

Correct option: B

CaS{O_4}.0.5{H_2}O

Option B (

CaS{O_4}.0.5{H_2}O

) is correct because when gypsum (

CaS{O_4}.2{H_2}O

) is heated to 393 K, it loses water molecules to form plaster of Paris (

CaS{O_4}.0.5{H_2}O

23 Hard

23 of 197

Remembering +4 | -1

Plumbo-solvency means dissolution of lead in:

View answer and explanation

Correct option: C

Ordinary water

Option C (Ordinary water) is correct because plumbo-solvency refers to the dissolution of lead in ordinary water, especially soft or acidic water.

24 Medium

24 of 197

Remembering +4 | -1

The different layers in graphite are held together by

View answer and explanation

Correct option: D

Van\;\mathrm{der}Waals'\;forces

Option D (Van der Waals' forces) is correct because the different layers in graphite are held together by weak van der Waals' forces.

25 Medium

25 of 197

Remembering +4 | -1

The common basic structural unit in silicates and silica is

View answer and explanation

Correct option: C

{SiO}_4^{4-}

Option C (

{SiO}_4^{4-}

) is correct because the basic structural unit in silicates and silica is the tetrahedral

{SiO}_4^{4-}

unit.

26 Medium

26 of 197

Analyzing +4 | -1

Which of the following is incorrect statement

View answer and explanation

Correct option: B

Pb{F_4}

is easily hydrolysed

Option B is the correct answer because

PbF_4

is ionic in nature, not easily hydrolysed due to the small size and high electronegativity of fluorine.

27 Easy

27 of 197

Understanding +4 | -1

Which of the following has lowest ionization enthalpy?

View answer and explanation

Correct option: C

{Sn}

Option C (

{Sn}

) is correct because ionization enthalpy generally decreases down a group, and while Pb has a slightly higher value than expected due to the poor shielding effect, Sn still has the lowest.

28 Hard

28 of 197

Remembering +4 | -1

Which of the following imparts green colour to flame:

View answer and explanation

Correct option: A

\mathrm{B}{\left( {\mathrm{OMe}} \right)_3}

Option A (

\mathrm{B}{\left( {\mathrm{OMe}} \right)_3}

) is correct because boron compounds, when heated, form

B_2O_3

which imparts a green color to the flame.

29 Easy

29 of 197

Remembering +4 | -1

Which variety of glass is used for manufacture of optical glasses

View answer and explanation

Correct option: B

Flint glass

Option B (Flint glass) is correct because flint glass is specifically used in the manufacture of optical lenses due to its high refractive index and low dispersion.

30 Medium

30 of 197

Remembering +4 | -1

The greatest percentage of CO is in:

View answer and explanation

Correct option: C

Water gas

Option C (Water gas) is correct because water gas contains the highest percentage of CO among the given options.

Revision notes and key takeaways

Review 14 TH GROUP ELEMENTS (P-BLOCK) in your textbook or class notes, then use this set to check your understanding.

Key Takeaways

✓ This set contains 197 single-correct-answer MCQs on 14 TH GROUP ELEMENTS (P-BLOCK).
✓ Try each question before opening its answer. Read the explanation where one is available.
✓ Sign in to save submitted answers. Revisit incorrect answers alongside your textbook or class notes.

Showing 1-30 of 197 questions

Continue Your Practice

📚 Switch Set (ALL)

Chapter Sets

ALL 197 MCQs EASY 85 MCQs HARD 10 MCQs MEDIUM 102 MCQs

0 /197

0✓ 0✗

0% Accuracy