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JEE CHEMISTRY MCQ: d & f- BLOCK ELEMENTS

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Application +4 | -1

A compound of a metal ion

{M^{x + }}

(Z = 24) has a spin only magnetic moment of

\sqrt {15}

Bohr Magnetons. The number of unpaired electrons in the compound are:

View answer and explanation

Correct option: D

3

Option D (3) is correct because the number of unpaired electrons is found using the formula

\mathrm{\mu } = \sqrt {n(n + 2)}

and solving for n when

\mathrm{\mu } = \sqrt{15}

, which gives n=3.

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