Skip to main content
Back to GRAVITATION

JEE PHYSICS MCQ: GRAVITATION

1 Medium
1 of 1
Application +4 | -1
If the radius of a planet is R and its density is ρ\rho, the escape velocity from its surface will be
View answer and explanation
Correct option: B
ve∝ρR{v_e} \propto \sqrt {\rho R}
Option B (ve∝ρR{v_e} \propto \sqrt {\rho R}) is correct because the escape velocity is directly proportional to the square root of the product of density and radius.

More Questions from GRAVITATION

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.