Given ${\rm{\vec A}} = \hat i + 2\hat j - 3\hat k$. When a vector ${\rm{\vec B}}$ is added to ${\rm{\vec A}}$, We get a unit vector along X=axis. Then,${\rm{\vec B}}$ is

NEET UG PHYSICS MCQ: MOTION IN PLANE

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Application +4 | -1

Given

\mathrm{\vec A} = \hat i + 2\hat j - 3\hat k

. When a vector

\mathrm{\vec B}

is added to

\mathrm{\vec A}

, We get a unit vector along X=axis. Then,

\mathrm{\vec B}

View answer and explanation

Correct option: A

- 2\hat j + 3\hat k

Option A (

- 2\hat j + 3\hat k

) is correct because when added to

\vec{A}

, it results in a unit vector along the x-axis.

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\mathrm{\vec a}\,and\,\mathrm{\vec b}

\mathrm{\vec a}\,and\,\mathrm{\vec b}

\overrightarrow P \,\,.\,\,\overrightarrow Q = 0\,and\,\overrightarrow P \,\, \times \,\,\overrightarrow Q = 0

\overrightarrow Q \,and\,\overrightarrow R

\vec{A}=3 \hat{i}+4 \hat{j}

\vec{B}=6 \hat{i}+8 \hat{j}

A

B

\overrightarrow{\mathrm{A}}

\overrightarrow{\mathrm{B}}

{\cot ^{ - 1}}\left( 2 \right)