JEE MATHEMATICS MCQ: 3D GEOMETRY SYSTEM

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Application +4 | -1

The vertex

A

of the triangle

A B C

is on the line

\vec{r}=\hat{i}+\hat{j}+\lambda \hat{k}

and the vertices

B

and

C

have respective position vectors

\hat{i}

and

\hat{j}

. Let

\Delta

be the area of the triangle and

\Delta \in\left[\frac{3}{2}, \frac{\sqrt{33}}{2}\right]

, then the range of values

\lambda

corresponding to '

A

' is

View answer and explanation

Correct option: D

[-4,-2] \cup[2,4]

Option D,

[-4,-2] \cup[2,4]

, is correct because it represents the range of

\lambda

values that satisfy the given area condition for the triangle.

More Questions from 3D GEOMETRY SYSTEM

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\left( { - 10,\;8} \right)

\left( { - 6,\;12} \right)

\left( {4,\; - 2} \right)

\left( { - 2,\;4} \right)

y z

(1,-2,4)

(3,-4

5)

p

2 x+y-3=0

3 x-y-2=0

x-p y+5=0

O\left( {0,0} \right),A\left( {a,0} \right)

B\left( {0,a} \right).

A(1,0,3)

B(4,7,1)

C(3,5,3)

\frac{x}{1}=\frac{y}{2}=\frac{z}{3}, \frac{x}{2}=\frac{y}{1}=\frac{z}{3}

\frac{x-1}{1}=\frac{2-y}{2}, z=3