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JEE PHYSICS MCQ: MOTION IN A STRAIGHT LINE

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Application +4 | -1
A particle is thrown vertically up with an initial velocity 9 m/s9 \mathrm{~m} / \mathrm{s} from the surface of Earth (take g=10 m/s2g=10 \mathrm{~m} / \mathrm{s}^2). The time (in seconds) taken by the particle to reach a height of 4 m4 \mathrm{~m} from the surface second time (in seconds) is
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Correct option: D
1.01.0
Option D (1.01.0) is correct because it is one of the two possible times when the particle reaches the specified height, and it is the second time.

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