Oxidation number of Sulphur in ${S_8}$ is

NEET UG CHEMISTRY MCQ: REDOX REACTIONS

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Oxidation number of Sulphur in

{S_8}

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Correct option: A

zero

Option A (zero) is correct because in elemental form, the oxidation number of any element is zero.

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{I_2}

\mathrm{MnO}_4^ - + {\mathrm{C}_2}\mathrm{O}_4^{2 - } + {\mathrm{H}^ + } \to \mathrm{M}{\mathrm{n}^{2 + }} + \mathrm{C}{\mathrm{O}_2} + {\mathrm{H}_2}\mathrm{O}

\mathrm{MnO}_4^ -

{\mathrm{C}_2}\mathrm{O}_4^{2 - }

{\mathrm{H}^ + }