JEE CHEMISTRY MCQ: HYDROCARBONS

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Friedel-Craft’s reaction does not occur in case of:

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Correct option: D

pyridine

Option D (pyridine) is correct because pyridine is a deactivated aromatic ring due to the nitrogen atom, and it forms a complex with the Lewis acid catalyst (

\mathrm{AlCl_3}

), preventing Friedel-Crafts reaction.

More Questions from HYDROCARBONS

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\mathrm{Ca}{\mathrm{C}_2} + {\mathrm{H}_2}\mathrm{O} \to X\xrightarrow{{{\mathrm{O}_3}/\frac{{{\mathrm{H}_2}\mathrm{O}}}{{\mathrm{O}{\mathrm{H}^ + }}}}}\mathrm{HCOOH} + \mathrm{HCOOH},X\;\mathrm{is}

In benzene, there is a delocalisation of π-electrons. Hence, each π-electron is attached by….carbon nuclei. Which statement is false? Assertion (A) In comparison to ethyl chloride, it is not easy to carry outnucleophilic substitution on vinyl chloride.

Reason (R) Vinyl group is an electron donating. If 2-oxopropanal and methanal are obtained by the reductive ozonolysis of compound (A), then the number of

\sigma

-bonds presents in Fischer-Tropsch process is used in the manufacture of: