JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Application +4 | -1

The value of the definite integral

\int\limits_{0}^1 \frac{x d x}{\left(x^3+16\right)}

lies in the interval

[a, b]

. Then smallest such interval is

View answer and explanation

Correct option: A

\left[0, \frac{1}{17}\right]

Option A ([0,

\frac{{1}}{{17}}

]) is correct because the integral's value lies within this interval, determined by bounding the integrand.

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