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JEE CHEMISTRY MCQ: 13 TH GROUP ELEMENTS (P-BLOCK)

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Boric acid on heating at 150∘C150^\circ C gives:
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Correct option: B
H2B4O7{\mathrm{H}_2}{\mathrm{B}_4}{\mathrm{O}_7}
Option B (H2B4O7{\mathrm{H}_2}{\mathrm{B}_4}{\mathrm{O}_7}) is correct because boric acid (H3BO3) when heated at 150°C gives tetraboric acid (H2B4O7{\mathrm{H}_2}{\mathrm{B}_4}{\mathrm{O}_7}).

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