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JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Application +4 | -1
If cos⁡xcos⁡2xcos⁡4xcos⁡8x=cosec⁡x16\cos x \cos 2 x \cos 4 x \cos 8 x=\frac{\operatorname{cosec} x}{16} then-
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Correct option: A
x=(4n+1)π32x=(4 n+1) \frac{\pi}{32}
Option A (x=(4n+1)π32x=(4 n+1) \frac{\pi}{32}) is correct because it represents the solution obtained after repeatedly applying the identity 2sin(x)cos(x) = sin(2x) and solving the resulting equation.

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