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JEE MATHEMATICS MCQ: PERMUTATIONS

1 Easy
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Application +4 | -1
mm men and nn women are to be seated in a row so that no two women sit together. If m>nm > n, then the number of ways in which they can be seated, is
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Correct option: A
m!(m+1)!(m−n+1)!\frac{{m!\left( {m + 1} \right)!}}{{\left( {m - n + 1} \right)!}}
Option A (m!(m+1)!(m−n+1)!\frac{{m!\left( {m + 1} \right)!}}{{\left( {m - n + 1} \right)!}}) is correct because it accounts for arranging the men and then placing the women in the gaps.

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