NEET UG PHYSICS MCQ: MOTION IN PLANE

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For angle

\ldots X \ldots

the projectile has maximum range and it is equal to ...X.... Here,

\mathrm{X}

and

\mathrm{Y}

refer to

View answer and explanation

Correct option: C

\frac{\pi}{4}

and

\frac{v_0^2}{g}

Option C (

\frac{\pi}{4}

and

\frac{v_0^2}{g}

) is correct because the maximum range is achieved at an angle of

\frac{\pi}{4}

radians (45 degrees) and the maximum range is

\frac{v_0^2}{g}

More Questions from MOTION IN PLANE

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\mathrm{\vec a}\,and\,\mathrm{\vec b}

\mathrm{\vec a}\,and\,\mathrm{\vec b}

\overrightarrow P \,\,.\,\,\overrightarrow Q = 0\,and\,\overrightarrow P \,\, \times \,\,\overrightarrow Q = 0

\overrightarrow Q \,and\,\overrightarrow R

\vec{A}=3 \hat{i}+4 \hat{j}

\vec{B}=6 \hat{i}+8 \hat{j}

A

B

\overrightarrow{\mathrm{A}}

\overrightarrow{\mathrm{B}}

{\cot ^{ - 1}}\left( 2 \right)