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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy
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Application +4 | -1
Let α,β,γ  and  δ\alpha ,\beta ,\gamma \;\mathrm{and}\;\delta are four positive real numbers such that their product is unity, then the least value of (1+α)(1+β)(1+γ)(1+δ)\left( {1 + \mathrm{\alpha }} \right)\left( {1 + \mathrm{\beta }} \right)\left( {1 + \mathrm{\gamma }} \right)\left( {1 + \mathrm{\delta }} \right) is
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Correct option: B
16
Option B (16) is correct because, by applying the AM-GM inequality, the least value of the expression is found to be 16.

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