JEE MATHEMATICS MCQ: MULTIPLE AND SUBMULTIPLE ANGLES

1 Easy

1 of 1

Application +4 | -1

\cos \,\,2\alpha = \frac{{3\cos \,\,2\beta - 1}}{{3 - \cos \,\,2\beta }}

, then

\tan \alpha

is equal to

View answer and explanation

Correct option: A

\sqrt 2 \,\,\tan \,\,\beta

Option A (

\sqrt 2 \,\,\tan \,\,\beta

) is correct because by applying componendo and dividendo,

\tan \alpha

can be expressed in terms of

\tan \beta

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