JEE MATHEMATICS MCQ: LIMITS

1 Easy

1 of 1

Analyzing +4 | -1

a > 0

and

\lim \limits_{{x \rightarrow \infty}}\left\{\sqrt{x^2+x+1}-(a x+b)\right\}=0

, then

(a, b)

lies on the line

View answer and explanation

Correct option: B

3 x+4 y-5=0

Option A (l=m) is correct because both limits, as x approaches infinity and negative infinity, evaluate to 1/2.

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