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JEE MATHEMATICS MCQ: ELLIPSE

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Application +4 | -1
If the eccentricities of the two ellipse x2169+y225=1\frac{x^2}{169}+\frac{y^2}{25}=1 and x2a2+y2b2=1\frac{x^2}{a^2}+\frac{y^2}{b^2}=1 are equal, then the value ab\frac{a}{b}, is
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Correct option: C
135\frac{13}{5}
Option C (135\frac{13}{5}) is correct because it is derived from equating the eccentricities of the two ellipses and solving for the ratio ab\frac{a}{b}.

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