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JEE MATHEMATICS MCQ: COMBINATIONS

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The number of ways of selecting two numbers a and b,a∈{2,4,6,….100}b, \quad a \in\{2,4,6, \ldots .100\} and b∈(1,3,5,…,99)b \in(1,3,5, \ldots, 99) such that 2 is the remainder when a+ba+b is divided by 23 is
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Correct option: A
108
Option A (108) is correct because by considering the possible values of λ\lambda in the equation a+b=23λ+2a+b = 23\lambda + 2, and counting the number of pairs (a, b) that satisfy the conditions, the total number of ways is 108.

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