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JEE PHYSICS MCQ: ELECTRIC POTENTIAL AND CAPACITANCE

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Application +4 | -1

A parallel plate capacitor of capacity

{C_0}

is charged to a potential

{V_0}

(i) The energy stored in the capacitor when the battery is disconnected and the separation is doubled

{E_1}

(ii) The energy stored in the capacitor when the charging battery is kept connected and the separation between the capacitor plates is doubled is

{E_2}.

Then

{E_1}/{E_2}

value is

View answer and explanation

Correct option: A

Option A (4) is correct because when the battery is disconnected, the energy stored doubles, and when the battery is connected, the energy stored halves, resulting in a ratio of 4.

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