JEE PHYSICS MCQ: NUCLEI

1 Medium

1 of 1

Application +4 | -1

Find the maximum energy that a beta particle can have in the following decay

{ }^{176} {Lu} \rightarrow{ }^{176} {Hf}+e+\bar{v} \text {. }

Atomic mass of

{ }^{176} {Lu}

175.942694 \mathrm{u}

and that of

{ }^{176} {Hf}

175.941420 \mathrm{u}

View answer and explanation

Correct option: A

1 . 182 \mathrm{~MeV}

Option A (

1 . 182 \mathrm{~MeV}

) is correct because it is calculated by finding the mass difference between the parent and daughter nuclei and converting it to energy using

E=mc^2

More Questions from NUCLEI