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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1
If for x∈(0, π2),  log⁡10sin⁡x+log⁡10cos⁡x=−1x \in \left( {0,\,\frac{\pi }{2}} \right),\,\,{\log _{10}}\sin x + {\log _{10}}\cos x = - 1 and log⁡10(sin⁡x+cos⁡x)=12(log⁡10n−1),  n>0{\log _{10}}\left( {\sin x + \cos x} \right) = \frac{1}{2}\left( {{{\log }_{10}}n - 1} \right),\,\,n > 0, then the value of nn is equal to:
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Correct option: C
12
Option C (12) is correct because solving the logarithmic equations and using trigonometric identities leads to n = 12.

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