JEE MATHEMATICS MCQ: BINOMIAL THEOREM

1 Hard

1 of 1

Application +4 | -1

If the sum of the coefficients in the expansion of

{\left( {\alpha \;{x^2} - 2x + 1} \right)^{35}}

is equal to the sum of the coefficient in the expansion of

{\left( {x - \alpha \;y} \right)^{35}},

then

\alpha =

View answer and explanation

Correct option: B

Option B (1) is correct because setting the sum of coefficients equal in both expressions leads to the equation (

\alpha

- 1)³⁵ = -(

\alpha

- 1)³⁵, which is only true when

\alpha

= 1.

More Questions from BINOMIAL THEOREM

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\left({ }^{10} C_0\right)^2-\left({ }^{10} C_1\right)^2+\ldots-\left({ }^{10} C_9\right)^2+\left({ }^{10} C_{10}\right)^2

a

d

\left( {n + 1} \right)

a{C_0} - \left( {a + d} \right){C_1} + \left( {a + 2d} \right){C_2} - ... + ...

(1-x)^{201}\left(1+x+x^2\right)^{200}

\left(\frac{1}{x}+2 x\right)^n

{x^5}

\frac{{1 + {x^2}}}{{1 + x}},\left| x \right| < 1,

\left(\begin{array}{c}2 n+1 \\ 0\end{array}\right)+\left(\begin{array}{c}2 n+1 \\ 3\end{array}\right)+\left(\begin{array}{c}2 n+1 \\ 6\end{array}\right)+\ldots=170

n