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NEET UG PHYSICS MCQ: UNITS & MEASUREMENTS

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Analyzing +4 | -1
A student performs an experiment for determination of g=4π2lT2g = \frac{{4{\pi ^2}l}}{{{T^2}}} and he commits an error of ∆l. For that he takes the time of n oscillations with the stop watch of least count Δ\DeltaT and he commits a human error of 0.1 sec. For which of the following data, the measurement of g will be most accurate Δl  ΔT  n  Ampli.of oscill\Delta l\,\,\Delta T\,\,n\,\,Ampli.of\,oscill
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Correct option: D
1 mm 0.1sec 50 1mm
Option D (1 mm 0.1sec 50 1mm) is correct because it minimizes the errors in length and time measurements by having a smaller least count and a larger number of oscillations.

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