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JEE CHEMISTRY MCQ: ALDEHYDES & KETONES & CARBOXYLIC ACIDS

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Analyzing +4 | -1
NaAlH4{NaAlH}_4 reduces an ester into HCHO{HCHO} and (CH3)2CHOH\left({CH}_3\right)_2 {CHOH}. Thus, ester is
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Correct option: A
HCOOCH(CH3)2{HCOOCH}\left({CH}_3\right)_2
Option A (HCOOCH(CH3)2{HCOOCH}({CH}_3)_2) is correct because it's the only ester that reduces to HCHO and (CH3)2CHOH when reacted with NaAlH4{NaAlH}_4.

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