The value of $\mathop {\lim }\limits_{x \to 0} \frac{{{{\sin }^2}x + \cos x - 1}}{{{x^2}}}$ is

JEE MATHEMATICS MCQ: LIMITS

1 Easy

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Application +4 | -1

The value of

\lim\limits_{x \to 0} \frac{{{{\sin }^2}x + \cos x - 1}}{{{x^2}}}

View answer and explanation

Correct option: B

\frac{1}{2}

Option B (

\frac{1}{2}

) is correct because the limit can be evaluated by using trigonometric identities and L'Hopital's rule or Taylor series.

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