The number of solutions of the given equation $\tan {\rm{\theta }} + \sec {\rm{\theta }} = \sqrt 3 $, where $0 < {\rm{\theta }} < 2{\rm{\pi }}$ is

JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

1 Easy

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Analyzing +4 | -1

The number of solutions of the given equation

\tan \mathrm{\theta } + \sec \mathrm{\theta } = \sqrt 3

, where

0 < \mathrm{\theta } < 2\mathrm{\pi }

View answer and explanation

Correct option: C

Option C (2) is correct because solving the trigonometric equation

\tan \theta + \sec \theta = \sqrt 3

in the interval

0 < \theta < 2\pi

yields two solutions.

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