JEE MATHEMATICS MCQ: BINOMIAL THEOREM

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Application +4 | -1

m,n,r

are positive integers such that

r < m,n,

then

{\;^m}{C_r} + {\;^m}{C_{r - 1}}{\;^n}{C_1} + {\;^m}{C_{r - 2}}{\;^n}{C_2} + \ldots + {\;^m}{C_1}{\;^n}{C_{r - 1}} + {\;^n}{C_r}

equals

View answer and explanation

Correct option: B

{\;^{m + n}}{C_r}

Option B (

{\;^{m + n}}{C_r}

) is correct because the given expression represents the coefficient of

x^r

in the expansion of

(1+x)^m(1+x)^n

, which simplifies to

(1+x)^{m+n}

More Questions from BINOMIAL THEOREM

Practice All Chapter MCQs →

\left({ }^{10} C_0\right)^2-\left({ }^{10} C_1\right)^2+\ldots-\left({ }^{10} C_9\right)^2+\left({ }^{10} C_{10}\right)^2

a

d

\left( {n + 1} \right)

a{C_0} - \left( {a + d} \right){C_1} + \left( {a + 2d} \right){C_2} - ... + ...

(1-x)^{201}\left(1+x+x^2\right)^{200}

\left(\frac{1}{x}+2 x\right)^n

{x^5}

\frac{{1 + {x^2}}}{{1 + x}},\left| x \right| < 1,

\left(\begin{array}{c}2 n+1 \\ 0\end{array}\right)+\left(\begin{array}{c}2 n+1 \\ 3\end{array}\right)+\left(\begin{array}{c}2 n+1 \\ 6\end{array}\right)+\ldots=170

n