JEE PHYSICS MCQ: ELECTRIC FIELDS AND CHARGES

1 Medium

1 of 1

Application +4 | -1

A charge having

e/m

equal to

{10^8}\,\,\,c/kg

and with velocity

3 \times {10^5}\,\,\,m/s

enters into a uniform magnetic field

B = 0.4\,\,\,{\text{tesla}}

at an angle

30^\circ

with direction of field. The radius of curvature will be

View answer and explanation

Correct option: A

3.75 \times {10^{ - 3}}\,\,\,m

Option A (15.75 cm) is correct because it calculates the new null point distance when the magnet is rotated, using the relationship between axial and equatorial magnetic fields.

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