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JEE MATHEMATICS MCQ: PARABOLA

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min⁡[(x1−x2)2+(3+(1−x12)−4x2)2],∀\min \left[\left(x_1-x_2\right)^2+\left(3+\sqrt{\left(1-x_1^2\right)}-\sqrt{4 x_2}\right)^2\right], \forall x1,x2∈Rx_1, x_2 \in R, is
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Correct option: B
3−223-2 \sqrt{2}
The correct answer is B (3−223-2 \sqrt{2}) because it represents the square of the shortest distance between the circle and the parabola, found using the common normal and subtracting the radius.

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