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NEET UG PHYSICS MCQ: NUCLEI

1 Hard
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Analyzing +4 | -1
The following deuterium reactions and corresponding reaction energies are found to occur
14N(d,p)15N,Q=8.53 MeV{ }^{14} {N}(d, p){ }^{15} {N}, Q=8.53 \,\mathrm{MeV}
15N(d,α)13C,Q=7.58 MeV{ }^{15} {N}(d, \alpha){ }^{13} {C}, Q=7.58 \,\mathrm{MeV}
13N(d,α)11B,Q=5.16 MeV{ }^{13} {N}(d, \alpha){ }^{11} {B}, Q=5.16\, \mathrm{MeV}
(The notation 14N(d,p)15N{ }^{14} {N}(d, p){ }^{15} {N} represent the reaction 14N+d→15N+p{ }^{14} {N}+d \rightarrow{ }^{15} {N}+p 24He=4.0026 amu;12H=2.014 amu;11H=1.0078 amu;n=1.0087 amu (1 amu=931 MeV).{ }_2^4 {He}=4.0026 \mathrm{~amu} ; { }_1^2 {H}=2.014 \,\mathrm{amu} ; { }_1^1 {H}=1.0078 \mathrm{~amu}; n=1.0087 \mathrm{~amu} \,(1 \mathrm{~a m u}=931 \mathrm{~MeV}). The QQ values of the reaction 11B(α,n)14N{ }^{11} {B}(\alpha, n){ }^{14} {N} is:
View answer and explanation
Correct option: C
0.05 MeV0.05 \mathrm{~MeV}
Option C is correct because by manipulating the given nuclear reactions and their Q-values, we can find the Q-value for the desired reaction, which is approximately 0.05 MeV.

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