If the length of rod A is $\left( {3.25\; \pm 0.01} \right)\;{\rm{cm}}$ and that of B is $\left( {4.19\; \pm 0.01} \right){\rm{\;cm}},$, then the rod B is longer than rod A by

$\left( {0.94{\rm{\;}} \pm 0.02} \right){\rm{\;cm}}$

$\left( {0.94{\rm{\;}} \pm 0.00} \right){\rm{\;cm}}$

$\left( {0.94{\rm{\;}} \pm 0.01} \right){\rm{\;cm}}$

$\left( {0.94{\rm{\;}} \pm 0.005} \right){\rm{\;cm}}$

JEE PHYSICS MCQ: UNITS & MEASUREMENTS

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Application +4 | -1

If the length of rod A is

\left( {3.25\; \pm 0.01} \right)\;\mathrm{cm}

and that of B is

\left( {4.19\; \pm 0.01} \right)\mathrm{\;cm},

, then the rod B is longer than rod A by

View answer and explanation

Correct option: C

\left( {0.94\mathrm{\;} \pm 0.02} \right)\mathrm{\;cm}

Option C

\left( {0.94\mathrm{\;} \pm 0.02} \right)\mathrm{\;cm}

is correct because the difference in lengths is calculated by subtracting the lengths and adding the uncertainties.

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