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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Analyzing +4 | -1

Let

f(x) =\frac{e^x}{1+e^x}

I_1 =\int\limits_{{f(-a)}}^{f(a)} x g(x(1-x)) d x

I_2 =\int\limits_{{f(-a)}}^{f(a)} g(x(1-x)) d x

then

I_2 / I_1

is

View answer and explanation

Correct option: D

2

The correct answer is D (2) because using the property f(a) + f(-a) = 1 and substituting (1-x) for x in the integral allows us to relate I1 and I2.

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\int \nolimits_0^\infty \,\,\log \,\,\left( {x + \frac{1}{x}} \right)\,\,\frac{{dx}}{{1 + {x^2}}}

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\int \nolimits_0^{{t^2}} \,\,x\;\,f\left( x \right)\,\,dx = \frac{2}{5}\,\,{t^5}

f\left( {\frac{4}{{25}}} \right)

equals The value of

\int\limits_{{0}}^{11}[x]^{3} . \mathrm{dx}

[*]

denotes the greatest integer function, is The integral

\int\limits_{2}^4 \frac{\log x^2}{\log x^2+\log \left(36-12 x+x^2\right)} d x

is equal to: The definite integral

\int\limits_{{-2}}^0\left(x^3+3 x^2+3 x+3+(x+1) \cos (x+1)\right) d x

I\,\,\left( {m,\,\,n} \right) = \int \nolimits_0^1 \,\,{t^m}\,\,{\left( {1 + t} \right)^n}\,\,dt

,then the expression for

I\left( {m,\,\,n} \right)

I\,\,\left( {m + 1,\,\,n + 1} \right)