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JEE MATHEMATICS MCQ: BINOMIAL THEOREM

1 Easy
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Application +4 | -1
If the fourth term in the expansion of {x(1log⁡x+1)+x1/12}6{\left\{ {\sqrt {{x^{\left( {\frac{1}{{\log x + 1}}} \right)}}} + {x^{1/12}}} \right\}^6} is equal to 200 and x>1,x > 1,, then xx is equal to
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Correct option: B
10
Option B (10) is correct because the value of x is found by setting the fourth term in the given expansion equal to 200 and solving the resulting equation for x, given that x > 1.

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