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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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The sum of the series 1x+1+2x2+1+22x4+1+....+2100x2100+1 \frac{1}{{x + 1}} + \frac{2}{{{x^2} + 1}} + \frac{{{2^2}}}{{{x^4} + 1}} + .... + \frac{{{2^{100}}}}{{{x^{{2^{100}}}} + 1}}\,, when x=2x = 2 is
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Correct option: D
1−21014101−11 - \frac{{{2^{101}}}}{{{4^{101}} - 1}}
The correct answer is D (1−21014101−11 - \frac{{{2^{101}}}}{{{{4^{101}} - 1}}}) because it is the result of telescoping the series and substituting x = 2.

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