JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Application +4 | -1

Let

\cos (\alpha+\beta)=\frac{4}{5}

and

\sin (\alpha-\beta)=\frac{5}{13}

, where

0 \leq \alpha, \beta \leq \frac{\pi}{4}

. Then,

\tan 2 \alpha

is equal to

View answer and explanation

Correct option: B

\frac{56}{33}

Option B (

\frac{56}{33}

) is correct because it is the value of

\tan 2\alpha

calculated using the given trigonometric values and the tangent addition formula.

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\left( {x,\,y} \right)

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\mathrm{X}

\theta \rightarrow \frac{\pi}{2}

\sin x+\cos x=\frac{\sqrt{7}}{2}

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0 < x < \pi

\cos x+\sin x=\frac{1}{2}

\tan x