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JEE PHYSICS MCQ: UNITS & MEASUREMENTS

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Application +4 | -1
In SI units, the dimensions of ∈0μ0\sqrt {\frac{{{ \in _0}}}{{{\mu _0}}}} is
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Correct option: D
A2T3M−1L−2A{}^2{T^3}{M^{ - 1}}{L^{ - 2}}
The correct answer is D (A2T3M−1L−2A{}^2{T^3}{M^{ - 1}}{L^{ - 2}}) because it correctly represents the dimensions of the given expression in SI units.

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