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JEE MATHEMATICS MCQ: RATE MEASURE

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If the velocity

v

of a particle moving along a straight line and its distance

s

from a fixed point on the line are related by

{\upsilon ^2} = {a^2} + {s^2},

then its acceleration equals

View answer and explanation

Correct option: B

s

Option B (s) is correct because the acceleration is equal to

s

when

{\upsilon ^2} = {a^2} + {s^2}

.

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