JEE MATHEMATICS MCQ: LIMITS

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Analyzing +4 | -1

f\left( x \right) = \left\{ {\begin{array}{cccccccccccccccccccc} {\frac{{\sin \{ \cos x\} }}{{x - \frac{\pi }{2}}},}\,{x \ne \frac{\pi }{2}} \\ {1,}\,{x = \frac{\pi }{2}} \end{array}} \right.

, where

\{.\}

represents the fractional part function, then

\lim \limits_{{x \rightarrow \pi / 2}} f(x)

, is

View answer and explanation

Correct option: C

Non-existent

Option C (Non-existent) is correct because the left-hand limit and right-hand limit are not equal, hence the limit does not exist.

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