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JEE PHYSICS MCQ: NUCLEI

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The gravitational force between a H{H}-atom and another particle of mass mm will be given by Newton's law : F=GM⋅mr2F=G \frac{M \cdot m}{r^2}, where rr is (in km{km} ) and
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Correct option: B
M=mproton +melectron −Bc2(B=13.6eV)M=m_{\text {proton }}+m_{\text {electron }}-\frac{B}{c^2}(B=13.6 {eV})
Option B (M=mproton +melectron −Bc2(B=13.6eV)M=m_{\text {proton }}+m_{\text {electron }}-\frac{B}{c^2}(B=13.6 {eV})) is correct because the mass of the hydrogen atom is slightly less than the sum of the masses of its constituents due to binding energy.

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