NEET UG CHEMISTRY MCQ: CO-ORDINATION COMPOUNDS

1 Hard

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Understanding +4 | -1

For a

{d^4}

metal ion in an octahedral field, the correct electronic configuration is

View answer and explanation

Correct option: A

t_{2g}^3e_g^1\,\,\,\mathrm{when}\,\,\mathrm{ }{\Delta _0} < P

Option A is correct because when Δ₀ < P, pairing energy is higher, leading to high spin configuration with electrons occupying both t2g and eg orbitals.

More Questions from CO-ORDINATION COMPOUNDS

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The complexes

\left[ {\mathrm{PtC}{\mathrm{l}_2}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}} \right]\mathrm{B}{\mathrm{r}_2}\mathrm{\;and\;}\left[ {\mathrm{PtB}{\mathrm{r}_2}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}} \right]\mathrm{C}{\mathrm{l}_2}\mathrm{\;}

are example for isomerism The total number of stereoisomers for the complex

\left[\mathrm{Cr}(\mathrm{Ox})_{2} \mathrm{ClBr}\right]^{3-}

(where

\text{ox =}

oxalate) is The value of

x

on the

{\left[ {\mathrm{Ni}{{\left( {\mathrm{CN}} \right)}_4}} \right]^x}

is: Excited state configuration of

\mathrm{M}{\mathrm{n}^{2 + }}

\mathrm{CuS}{\mathrm{O}_4}

decolourises on addition of KCN, the product is: The IUPAC name of

{\mathrm{K}_2}\left[ {\mathrm{Ni}{{\left( {\mathrm{CN}} \right)}_4}} \right]