JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

1 of 1

Application +4 | -1

x=1998

!, then value of the expression

\frac{1}{\log _{2} x}+\frac{1}{\log _{3} x}

+\ldots \ldots+\frac{1}{\log _{1998} \mathrm{x}}

equals-

View answer and explanation

Correct option: C

Option C (1) is correct because using the change of base formula and properties of logarithms simplifies the expression to 1.

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