JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy

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Analyzing +4 | -1

I_1=\int\limits_{0}^1 2^{x^2} d x, I_2=\int\limits_{0}^1 2^{x^3} d x, I_3=\int\limits_{1}^2 2^{x^2} d x

and

I_4=\int\limits_{1}^2 2^{x^3} d x

then

View answer and explanation

Correct option: B

I_1 > I_2

Option B (

I_1 > I_2

) is correct because

2^{x^3} < 2^{x^2}

for

0 < x < 1

, implying the integral of

2^{x^2}

from 0 to 1 is greater.

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