JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

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Determine the wavelength of a photon of electromagnetic radiation having energy

2.99 \times 10^{12} \mathrm{~erg} \mathrm{~mol}^{-1} \left(\mathrm{h}=6.625 \times 10^{-34} \mathrm{~Js}\right)

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Correct option: A

4000 ~\mathop {\text{A}}\limits^ \circ

Option A (

4000 ~\mathop {\text{A}}\limits^ \circ

) is correct because it is the wavelength calculated using the energy of the photon and Avogadro's number.

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n^{\text {th }}

\mathrm{A}

\times 10^{12}

\frac{1}{{ }^{\prime} \mathrm{B}^{\prime}}

\ell = 1,\,\,m = 0

1.25 \times {10^{ - 13}} \times {A^{1/3}}\mathrm{cm}.