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JEE PHYSICS MCQ: SYSTEM OF PARTICLES

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If applied torque on a system is zero, i.e.,

\tau=0

, then for that system

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Correct option: B

\alpha=0

Option B (α=0) is correct because if the applied torque is zero, the angular acceleration is also zero.

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It is easier for a swimmer jumping into water from a height to describe a loop in the air by A uniform thin rod

\mathrm{AB}

\mathrm{L}

has linear mass density

\mu(x)=a+\frac{b x}{L}

x

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\mathrm{A}

\mathrm{CM}

of the rod lies at a distance of

\left(\frac{7}{12}\right) \mathrm{L}

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\mathrm{b}

are related as : A solid metal ring and a disc of same radius and mass are rotating about their diameters with same angular frequency. The ratio of their respective rotational kinetic energy values is When a torque acting upon a system is zero, then which of the following will be constant A point particle of mass

1.0 \mathrm{~g}

is rotating in a circle of diameter

8 \mathrm{~cm}

. Its moment of inertia will be The angular velocity of a particle is given by

\omega = {t^4} + 2{t^3}

then its angular acceleration of the particle at

t = 1\,sec

\left( {rad\,{s^{ - 2}}} \right)