NEET UG PHYSICS MCQ: ELECTROMAGNETIC WAVES

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The electric field and magnetic field components of an electromagnetic wave going through vacuum is described by

\begin{array}{l} E_{x}=E_{0} \sin (k z-\omega t) \\ B_{y}=B_{0} \sin (k z-\omega t) \end{array}

Then the correct relation between

{E}_{0}

and

{B}_{0}

is given by

View answer and explanation

Correct option: C

{kE}_{0}=\omega {B}_{{o}}

Option C (

{kE}_{0}=\omega {B}_{{o}}

) is correct because the ratio of the electric field amplitude to the magnetic field amplitude is equal to the speed of light, and

c = \omega/k

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