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JEE CHEMISTRY MCQ: HYDROCARBONS

1 Easy
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Application +4 | -1
Which is the most suitable reagent among the following distinguish compound (III) from rest of the compounds
(I) CH3−C≡C=CH3C{H_3} - C \equiv C = C{H_3} (II) CH3−CH2−CH2−CH3C{H_3} - C{H_2} - C{H_2} - C{H_3}
(III) CH3−CH2−C≡CHC{H_3} - C{H_2} - C \equiv CH (IV) CH3−CH=CH2C{H_3} - CH = C{H_2}
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Correct option: D
Ammonical Silver nitrate
Option D (Ammonical Silver nitrate) is correct because it reacts specifically with terminal alkynes due to the presence of acidic hydrogen atoms.

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