Skip to main content
Back to SEQUENCE OF SERIES

JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy
1 of 1
Application +4 | -1
The 9th 9^{\text {th }} term of the series 27+9+525+367+⋯27+9+5 \frac{2}{5}+3 \frac{6}{7}+\cdots will be
View answer and explanation
Correct option: A
110171 \frac{10}{17}
Option A (110171 \frac{10}{17}) is correct because the series can be rewritten as 27/1,27/3,27/5,...27/1, 27/3, 27/5,..., and the 9th term is 27/(2∗9−1)=27/17=1101727/(2*9-1) = 27/17 = 1 \frac{10}{17}.

More Questions from SEQUENCE OF SERIES

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.