JEE PHYSICS MCQ: THERMODYNAMICS

1 Medium

1 of 1

Application +4 | -1

Air expands from 5 lit to 10 lit at 2 atm pressure. External work done is

View answer and explanation

Correct option: D

1000 J

Option D (1000 J) is correct because the external work done during expansion at constant pressure is calculated using

W = P\Delta V

More Questions from THERMODYNAMICS

Practice All Chapter MCQs →

0.25\,\,{m^3}

{10^3}N/{m^2},

T

P

V

\left( {\gamma = \frac{{{C_p}}}{{{C_v}}}} \right)