JEE PHYSICS MCQ: UNITS & MEASUREMENTS

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Analyzing +4 | -1

The position of a particle at time t is given by the relation 

x\left( t \right) = \left( {\frac{{{v_0}}}{\alpha }} \right)\left( {1 - {c^{ - \alpha t}}} \right)

, where 

{v_0}

 is a constant and 

\alpha > 0

. The diemensions of 

{v_0}

and 

\alpha

 are respectively

View answer and explanation

Correct option: A

{M^0}{L^1}{T^{ - 1}}\,{\text{and}}\,{T^{ - 1}}

Option A (

{M^0}{L^1}{T^{ - 1}}\,{\text{and}}\,{T^{ - 1}}

) is correct because it correctly identifies the dimensions of velocity and inverse time respectively.

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